Program to find transpose of a matrix in C
Program to find
transpose of a matrix in C
·
To
understand this C program you should have knowledge of Two dimensional array.
Two-dimensional array:
Two dimensional array are represented in the form of matrix and tables.
The arrays have two subscript: one represents the row and other represent the
columns.
The transpose of a
matrix is simply a flipped version of the original matrix. We can transpose a
matrix by switching its rows with its columns.
Program:
#include
<stdio.h>
#include
<conio.h>
void
transpose (int [] [10], int, int);
void
display (int [] [10], int, int);
void main
()
{
int a[10]
[10];
int I, j,
rows, cols;
clrscr ();
printf (“Enter
no. of rows in a matrix(<10): “);
scanf (“%d”,
&rows);
printf (“
Enter no. of columns in the matrix (<10) :”);
scanf (“%d”,
&cols);
printf (“ -
- - - - Enter row wise %d integer of matrix - - - - - \n”, rows, cols);
for (i=0;
i<rows; i++)
for (j=0;
j<cols; j++)
{
scanf (“%d”,
&a[i] [j] );
}
display (a,
rows, cols);
transpose (a,
rows, cols);
getch ();
}
void
transpose ( int x[] [10], int p, int q)
{
int i, j,
k;
int y[10] [10];
for (i=0;
i<p; i++)
for (j=0;
j<q; j++)
{
y [i] [j] =
x [i] [j];
}
printf (“\n
- - - - - Transpose is - - - - -“);
display (y,
q, p);
}
void
display (int c[] [10], int m, int n)
{
int i, j;
printf (“
\n - - - - - Displaying %d by %d data - - - - - \n”, m, n);
for (i=0;
i<m; i++)
{
for ( j=0;
j<n; j++)
printf (“%d\t”,
c[i] [j]);
printf (“\n”);
}
}
OUTPUT:
Enter no of
rows in the matrix (<10): 2
Enter no.
of columns in the matrix (<10) :3
- - - - -
Enter row wise %d integer of matrix - - - - -
2 3
4 55 66
77
- - - - -
Displaying 2 by 3 data - - - - -
2 3
4
55 66
77
- - - - -
Transpose is - - - - -
- - - - -
Displaying 3 by 2 data - - - - -
2 55
3 66
4 77
Explanation of program:
The
transpose of matrix is calculated by interchanging rows and columns of the
matrix .
Tips To Remember:
1. The transpose of
the matrix is defined as the matrix that is obtained by interchanging the
rows of a matrix to columns. If the matrix is of the order m*n then transpose
of the matrix will be n*m.
2. In matrix
multiplication, the number of columns in the first matrix should be equal to
the number of rows in the second matrix. Each row of the first matrix is
multiplied with the columns of the second matrix then added to get the
element of the result.
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